Math, asked by anamikaribhurishi, 4 months ago

The age of A is 5 years more than that of B. 5 years ago the ratio of their ages was 3:2. Find their present ages.

Answers

Answered by naseemahmad56

1

Step-by-step explanation:

Let us assume that 5 years ago, the age of A was 3x and that of B was 2x, x being the HCF of the two numbers.

Now, the present ages of A & B are (3x+5) and (2x+5) respectively.

Age of A is 5 years more than that of B.

As per the given condition :

(3x+5)-(2x+5)=5

=>x=5

Therefore the present age of A = 3x+5 = 20

The present age of B = 2x+5 = 15.

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