Math, asked by hhiihihi8442, 1 year ago

The age of a is 5 years more than the b then 5 years ago the ratio of their ages was 3 ratio 2. Find their present ages

Answers

Answered by Anonymous
98

Answer :-

Let the age of “B” be x yrs ;

Age of A = x + 5 yrs.

5 years ago ;

Age of “A” = x + 5 - 5 = x

Age of “B” = x - 5

According To The Question :-

=> x/x - 5 = 3/2

=> x × 2 = 3 (x - 5)

=> 2x = 3x - 15

=> 3x - 2x = 15

=> x = 15

Present Age of “B” = 15 years

Present Age of “A” = 15 + 5 = 20 years.

Hence, The Present Age of “A” is 20 years ;

Present Age of “B” is 15 years.

Answered by BoyBrainly
7

Let ,

The Present Age of " B " Be x Years

The Present Age Of " A " = 5 + x Years

5 Years Ago ;

The Age of B = x - 5 Years

The Age of A = x Years

 \bold{ \underline{According \:  to  \: the  \: Questions \:  ,  \:   \: \: }}

   \bold{\to\frac{x}{x - 5} } =  \bold{ \frac{3}{2} } \\ \\  \bold{  \to2(x)= 3(x - 5)} \\ \\  \bold{   \to2x = 3x - 15 }\\  \\  \bold{ \to2x - 3x =  - 15 }\\  \\  \bold{ \to -  \: x  =  - 15 }\\  \\   \bold{\to x = 15}

 \therefore  \: The Present Age of B and A Is 15 Years And 20 Years

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