Math, asked by adi51515, 1 year ago

the age of A is five years more than of B. 5 years ago, the ratio of their ages of 3:2. find their present ages.


niranjanmanjulpaantc: let age of A is X yrs and age of B is (X-5) yrs.5 years ago age of A was (X-5) years and age of B was (X-10) years. by given conditions X-5/X-10=3/2;2X-10=3X-30;-X=-20; X=20 ; age of A is 20 yrs and age of B is 20-5=15 years
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MuraliPobbathi: 3ratio-2ratio=1ratio----5 years
5 years ago
3*5=15 years
2*5=10 years
Present
20,15 years
sanjeevgarg: ans-20,20-5=15
xploredude: 20&15:)
mandeepbajwa: ans20,20-5=15
Ankitkuniyal1907: Let us assume that 5 years ago, the age of A was 3x and that of B was 2x, x being the HCF of the two numbers.

Now, the present ages of A & B are (3x+5) and (2x+5) respectively.

Age of A is 5 years more than that of B.

As per the given condition :

(3x+5)-(2x+5)=5

=>x=5

Therefore the present age of A = 3x+5 = 20

The present age of B = 2x+5 = 15.

Hence the solution.
SahilSinghRajpoot: 3:4

Answers

Answered by lohithanaidu
319
Let the age of A be 'x' and the age of B be 'y'.
A is five years more than that of B⇒x=y+5-----(1)
5 years ago,the ratio of their ages is 3:2
⇒(x-5)/(y-5)=3/2
⇒2x-10=3y-15
⇒2x-3y=-5------(2)
Substituting (1) in (2),
⇒2(y+5)-3y=-5
⇒2y+10-3y=-5
⇒-y=-15
y=15.
From (1),x=y+5
⇒x=15+5
x=20.
∴A is 20 years old and B is 15 years old.

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Answered by Panzer786
450
Heya !!!

Let The present age of B be X years.

Then the age of A = ( X + 5) years.

Before Five years age of A = ( X +5 - 5) = X years.

Before Five years age of B = ( X -5) years.

According to question ,

A : B = 3:2

X / X -5 = 3/2

2 ( X )= 3 ( X -5)

2X = 3X -15

3X - 2X = 15

X = 15 years.

Present age of B = X = 15 years

And,

Present age of A = X +5 = 15+5 = 20 years.

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