Question

the age of A is five years more than of B. 5 years ago, the ratio of their ages of 3:2. find their present ages.

Answer 1

Hey

Here is your answer,

Let us assume that 5 years ago, the age of A was 3x and that of B was 2x, x being the HCF of the two numbers.

Now, the present ages of A & B are (3x+5) and (2x+5) respectively.

Age of A is 5 years more than that of B.

As per the given condition :

(3x+5)-(2x+5)=5

=>x=5

Therefore the present age of A = 3x+5 = 20

The present age of B = 2x+5 = 15.

Hence the solution.

Hope it helps you

Answer 2

Let present age of B = x
And present age of A = x + 5



Five years ago,

$\frac{x + 5 - 5}{x - 5} = \frac{3}{2} \\ \\ \\ \frac{x }{x - 5} = \frac{3}{2} \\ \\ \\ 2x = 3(x - 5) \\ \\ 2x = 3x - 15 \\ \\ 15 = 3 x - 2x \\ \\ 15 = x$


Present age of B= x = 15 years
Present age of A = x + 5 = 20




I hope this will help you


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