the age of a man 9 years after is square of the age 33 years ago.Find the present age of the man
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let the present age of tje man be x years.
x+9=(x-33)^2
x+9=x^2+33*33 -2*33*x
x+9=x^2+1089 -66x
x^2-67x+1080=0
using middle term splliting
x^2 -27x-40x+1080=0
x(x-27)-40(x-27)
(x-27)(x-40)
his age can be either 27 or 40
x+9=(x-33)^2
x+9=x^2+33*33 -2*33*x
x+9=x^2+1089 -66x
x^2-67x+1080=0
using middle term splliting
x^2 -27x-40x+1080=0
x(x-27)-40(x-27)
(x-27)(x-40)
his age can be either 27 or 40
Answered by
2
Answer:
Let,
The present age of the man be x years
33 years ago, his age was (x-33) years
9 years later, his age will be (x+9) years
A/Q,
(x+9) =(x-33)*2
= x+9 =x*2-2.x.33+33*2
= x+9 =x*2 -66x+1089
= x+9-x*2+66x-1089=0
= -x*2+67x-1080=0
= x*2-67x+1080=0
= x*2-(40+27)x+1080=0
= x*2-40x-27x+1080=0
= x(x-40)-27(x-40)=0
= (x-40)(x-27)=0
Either,
x-40=0. or. x-27=0
= x=40. =x=27
The present age of the man can either be 27 or 40
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