Math, asked by laxmirajaiahp6691, 1 year ago

The age of a man is four times of his son.five years ago ,the man was nine times as old as his sin was at that time.the present age of the man is.

Answers

Answered by asalmanyunus
0
the age of boy=x
the age of father=4x
suposse the boy was is x=8 year old
then his father is=4x=4(8)=32year
5 year ago....
his son age=8-5years=3years
his age=32-5years=27years
then the man was nine times as old as his son
now his age is 27
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