the age of a man is same as as his wife's ages with the digits reversed. the sum of their ages is 99 years and the man is 9 years older than hi wife. how old is the man
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let the man age = 10x +y
wife age = 10y +x
sum of the ages =99
10x+y +10y +x =99
11x +11y =99
divide each term with 11
x+y =9 ----(1)
man age = wife age+9
10x +y = 10y +x+9
10x-x +y -10y =9
9x -9y =9
divide each term with 9
x-y =1 ---(2)
add (1) and (2)
2x =10
x= 10/2
x= 5
plug x=5 in (1)
y= 4
therefore
man age =10x+y
= 10*5 +4
=50+4
= 54
wife age = 45
wife age = 10y +x
sum of the ages =99
10x+y +10y +x =99
11x +11y =99
divide each term with 11
x+y =9 ----(1)
man age = wife age+9
10x +y = 10y +x+9
10x-x +y -10y =9
9x -9y =9
divide each term with 9
x-y =1 ---(2)
add (1) and (2)
2x =10
x= 10/2
x= 5
plug x=5 in (1)
y= 4
therefore
man age =10x+y
= 10*5 +4
=50+4
= 54
wife age = 45
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