The age of a man is same as his wife 's age with the digits reserved the man is 9 years old then and his wife if the sum of of there ages is 99 years then how old is the man
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Answered by
3
let woman x
man 9+x
9+x+x=99
2x=99-9
2x=90
x=90/2
=45
hence, woman=45
man=45+9=54
hope it helps you
rishita1822:
thankyou so much
Answered by
0
let age of man be 10x+y
age of wife be 10y+x
sum of there ages=99
10x+y+10y+x=99
11X+11y=99
dividing by 11
X+y=9_(1)
man age -wife age=9
10x+y-(10y+x)=9
9x-9y=9 dividing by 9
x-y=1
X=y+1
substitute in 1
y+1+y=9
2y=9-1 =8
y=4
so x=y+1=5
hence man age is 10x+y=10*5+4=54
wife age is 45
age of wife be 10y+x
sum of there ages=99
10x+y+10y+x=99
11X+11y=99
dividing by 11
X+y=9_(1)
man age -wife age=9
10x+y-(10y+x)=9
9x-9y=9 dividing by 9
x-y=1
X=y+1
substitute in 1
y+1+y=9
2y=9-1 =8
y=4
so x=y+1=5
hence man age is 10x+y=10*5+4=54
wife age is 45
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