Math, asked by harvi99, 1 year ago

The sum of weights of Raju and Anu is 85 Kg.If half the weight of Raju is equal to 4 by 9th of the weight of Anu ,determine the weights of Raju and Anu.
Class 10 question please help me fast......​


harvi99: please answer it fast

Answers

Answered by Rishik2101
1

Explanation is as follows:

Let Raju's weight be x Kg.

So Anu' s weight be (85-x) Kg.

According to the question,

1/2 × x = (4/9) × 85-x

x/2 = (340-4x) / 9

On solving till last, we get.

9x = 2(340-4x)

9x = 680 - 8x

9x+8x = 680

17x = 680

x = 680/17

x = 40

x= 40

85-x = 85-40 = 45

Therefore, Raju's age is 40 years and Anu' s age is 45 years.

Please mark it BRAINLIEST


deepukk2004: Explanationisasfollows:
LetRaju'sweightbexKg.

SoAnu' sweightbe(85-x)Kg.

Accordingtothequestion,

1/2×x=(4/9)×85-x

x/2 = (340-4x) / 9

Onsolvingtilllast,weget.

9x = 680 - 8x

9x + 8x = 680

17x = 680

x = 680/17

x = 40

Therefore,Raju'sageis62andAnu' sageis23.

PleasemarkitBRAINLIEST

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deepukk2004: their ages are 440 and 45
deepukk2004: sorry raju weight is 40
deepukk2004: anu weight is 45
Answered by deepukk2004
0

Answer:

Step-by-step explanation:

so sum of raju and anu be x+y = 85

1/2x = 4/9y

x=4/9 x 2/1 y

x= 8/9y

8/9y+y =85

2y = 85 x 9/8

2y= 95.625

y = 95.625/2

y = 47.8125

x =37.1875


Rishik2101: But I know there ages can't be in decimal.
deepukk2004: sorry by mistake
deepukk2004: but your answer is also wrong
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