the age of a man is three times the sum of the ages of his 2 children and 5 year hence his age is doubled the sum of their ages find his present age
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if the age of two children is 3,2then the age of man is20
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Present age of man is 45 years.
Given :-
The age of a man is three times the sum of the ages of his two sons.
5 years hence, his age will be double the sum of their ages.
To find :-
Present age of man.
Solution :-
Let ,
Man's present age = x years
Present age of 1st son = y years
Present age of 2nd son = z years
The age of a man is three times the sum of the ages of his two sons.
➪ x = 3(y+z)
➪ y+z = x/3 ..................(i)
5 years hence, his age will be double the sum of their ages
5 years hence,
Man's age = (x+5) years
Age of 1st son = (y+5) years
Age of 2nd son = (z+5) years
➪ x+5 = 2[(y+5)+(z+5)]
➪ x+5 = 2(y+z+10)
[ put y+z = x/3 from eq (i)]
➪ x+5 = 2(x/3 + 10)
➪ x+5 = 2x/3 + 20
➪ x - 2x/3 = 20-5
➪ x/3 = 15
➪ x = 45
† Present age of man is 45 years.
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