Question

The age of a man is twice the sum of tha ages of his two sons, and five years ago his age was thrice the sum of their ages. find his present age. find also the sum of the ages of the two sons.​

Answer 1

let the man age be xy

sum of sons age is x+y

xy = 2(x+y)

Five years ago

xy-5 = 3(x+y)-5
xy-5= 3x +3y-5

Answer 2

Answer: The present age of father = 20 years,

The sum of ages of the two sons = 10 years

Step-by-step explanation:

Let the sum of the ages of two son,

⇒ The age of father = 2x

The sum of ages of two sons before 5 years = x - 5,

While the age of father before 5 years = 2x - 5

According to the question,

2x - 5 = 3(x-5)

⇒ 2x - 5 = 3x - 15

⇒ 2x - 3x = -15 + 5

⇒ -x = -10

⇒ x = 10

Hence, the present sum of ages of the two sons = x = 10 years

And, the present age of father = 2x = 20 years