Question

the age of a mother and daughter are 31 and 7 years respectively the number of years in which the mother's age will be 3 by 2 times that of the daughter is

Answer 1

The number of years in which the mother's age will be 3 by 2 times that of the daughter is 41 years.

Step-by-step explanation:

Given:

The age of a mother and daughter are 31 and 7 years respectively.

The mother's age will be 3 by 2 times that of the daughter.

To Find:

The number of years in which the mother's age will be 3 by 2 times that of the daughter.

Solution:

As given,the age of a mother and daughter are 31 and 7 years respectively.

Mother age= 31 years

Daughter age=7 years

Let after p years ,the mother's age will be 3 by 2 times that of the daughter.

As given,the mother's age will be 3 by 2 times that of the daughter.

$(31+p)= \frac{3}{2} (7+p)$

$2(31+p)= 3 (7+p)$

$62+2p=21+3p$

$62-21=3p-2p$

$p=41\ years$

Thus,the number of years in which the mother's age will be 3 by 2 times that of the daughter is 41 years.

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Answer 2

Answer:

The number of years in which the mother's age will be 3 by 2 times that of the daughter is 41 years.

Step-by-step explanation:

Explanation:

Given in the question that, the age of a mother and daughter are 31 and 7 years.

Let the number of years be x in which the mother's age will be 3 by 2 times that of the daughter.

Step 1:

From the question we have,

Mother age = 31 years

Daughter age = 7 years

According to the question, the mother's age will be 3 by 2 times that of the daughter.

⇒ 31 + x = $\frac{3}{2}$(7 + x)

⇒ 2(31 +x) = 3(7 + x)

⇒62 + 2x = 21 + 3x

⇒62 - 21 = 3x - 2x = x

⇒41 = x

Final answer:

Hence,  the number of years in which the mother's age will be 3 by 2 times that of the daughter is 41 years.

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