Math, asked by nethrabjm167, 5 months ago

The age of a mother is 25 years more than that of her daughter. Five year hence,

mother’s age will be twice that of the daughter’s age. Find their present ages.​

Answers

Answered by mithilesh9848
3

Answer:

Present age of mother = 45

present age of daughter =20

Step-by-step explanation:

let daughter's age be x

and mother's age be y

1 equation:

y=25+x

=x-y+25

2 equation:

(y+5)=2(x+5)

y+5=2x+10

=2x-y+5

By comparing both equations

x=20

y=45

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Answered by sengarvansh727
0

Step-by-step explanation:

let the age of daughter be x

the age of mother be x+25

ATQ

daughter =2(x+5)

mother=x+25+5

=2(x+5)=x+25+5

=2x+10=x+30

=2x-x=30-10

=x=20

ATQ

daughter=20

mother =x+25

=20+25

=45

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