The age of David is half the age of his mother. If the sum of their ages is 54 years,find the age of David
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Answer:
let age of David's mother= X
ACC. to que
age of David = 1/2x
X+1/2x=54
2x+X/2=54
3x/2=54
3x=108
X=108÷3
X=36
hence,age of David=36years
Answered by
0
Answer:
let age of David 's mother =x
David 's age =x/2
according to question
x+(x/2)=54
=>(2x+x)/2=54
=>3x=54×2
=>3x=108
=>x=108/3
=>x=36
David 's mother's age =36
David 's age =36/2=18.
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