Question

The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is

Answer 1

Answer:

7:3

Step-by-step explanation:

Let son's age 10 years ago be x.

Father's age 10 years ago = 3x

2(x+20) = (3x+20)

x = 20

10 years ago, father's age = 60 years and son's age = 20 years

Ration of their present age = 70:30 = 7:3

Answer 2

Answer:

Let the age of Father and son be x and 3x years respectively.

After Ten years,

Age of father = x + 10 years

Age of son = 3x + 10

According to Question now,

(3x + 10) + 10 = 2(x + 10) + 10

3x + 20 = 2(x + 20)

3x + 20 = 2x + 40

3x - 2x = 40 - 20

x = 20 years.

Therefore, Required ratio :

(3x + 10) : (x + 10)

3(20) + 10 : 20 + 10

60 + 10 : 30

70 : 30

7 : 3

Therefore, the required ratio is 7:3.