Question

The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:

Answer 1

let the present age of fathrr be x and they of son be y
According to question,
x-10=3 (y-10)
x-10=3y-30
x-3y=-20_____________(1)
Also,
x+10=2 (y+10)
x+10=2y+20
x-2y=10_________(2)
Subtracting (1) and (2) we get
-y=-30
y=30
Puy y=30 in (2) we get
x=50
Hence father's age =x=50
and son's age=y=30
Hope it helps
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Answer 2

father age =x
son age=y

x-10=3 (y-10)
x-3y=-20

x+10=2 (y+10)
x-2y=-10

x-3y=-20
-x+2y=-10

y=30

x=70

x:y=7:3