a car moving in a straight road with a uniform motion . the given table gives the speed of the car with instant of time speed- 5,10,15,20,25,30 time - 10,20,30,40,50 draw a speed time graph and find the acceleration of car an d distance travelled by a car in 50 sec
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make time on x axis and speed on y axis mark points like 5,10,15,20 on both axis join points of speed with time like 5 with 10 ,10 with 20 mark and join th points
ishaa4:
but how to find acceleration of the car and distance travelled by a car in 50 sec?
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Answer:
Graph of the table : Draw X - axis and Y - axis on the graph with appropriate scale.
Let 1 cm = 10 s on X-axis.
Let 1 cm = 5 m on Y-axis.

(i) Acceleration means slope of graph AB
BC / AC = 30 - 5 / 50 - 0 = 25 / 30 = 0.5 m / s2
(ii) Distance travelled by car = Area of trapezium OABD
= 1 /2 (AO + BD) × OD
= 1 / 2 (5 + 30) × 50 = 875 m
Explanation:
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