Question

The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:

Answer 1

Let 3x and x years be the ages  of father and son 10 years ago

Then, (3x+10)+10 = 2{(x+10)+10}

3x+20 = 2x+40

x=20

Required ratio = (3x+10):(x+10) = 70:30 = 7:3

Answer 2

Answer:

Let the age of Father and son be x and 3x years respectively.

After Ten years,

• Age of father = x + 10 years
• Age of son = 3x + 10

According to Question now,

(3x + 10) + 10 = 2(x + 10) + 10

3x + 20 = 2(x + 20)

3x + 20 = 2x + 40

3x - 2x = 40 - 20

x = 20 years.

Therefore, Required ratio :

• (3x + 10) : (x + 10)

• 3(20) + 10 : 20 + 10

• 60 + 10 : 30

• 70 : 30

• 7 : 3