Question

The age of father is 2 years more than five times the age of his son.
If the sum of their ages is 38 years, find the age of each of them.

Answer 1

Step-by-step explanation:

Let the son's age be x

father's age = 5x + 2

sum of their ages = 5x + 2 + x = 38

= 6x + 2 = 38

= 6x = 38 - 2

= x = 36/6

x = 6

Father's age = 5×6 + 2 = 32 years

Son's age = 6 years

Answer 2

Answer:

Father's age is 32 years and his son's age is 6 years.

Step-by-step explanation:

Given :-

• The age of father is 2 years more than 5 times the age of his son.
• The sum of their ages is 38 years.

To find :-

• Their ages.

Solution :-

Let the present age of son be x years.

★ The age of father is 2 years more than 5 times the age of his son.

Then,

• Father's age = (5x+2) years

★ The sum of their ages is 38 years.

${\underline{\sf{According\:to\:the\: question,}}}$

x + 5x+2 = 38

→ 6x + 2 = 38

→ 6x = 38-2

→ 6x = 36

→ x = 36/6

→ x = 6

Therefore,

† Present age of son = 6 years

† Present age of father = 5×6+2 = 32 years

_________________

★ Verification ★

• Father's age = 32 years
• Son's age = 6 years

Sum of their ages = 38

→ 32+6 = 38

→ 38 = 38

Hence Verified !