Math, asked by sujataroutrayrav1970, 10 months ago

the age of father is 3 times the age of son 5 years ago father was five times as old as his son was find there present age​

Answers

Answered by kvkeerthana
1

Answer:

Son's age = 10 years

Father's age = 30 years

Step-by-step explanation:

Son's age = x

Father's age = 3x

Five years ago:

Son's age = x - 5

Father's age = 3x - 5

5(x - 5) = 3x - 5

5x - 25 = 3x - 5

5x - 3x = -5 + 25

2x = 20

x = 20/2

x = 10

Son's age = x = 10 years

Father's age = 3x = 3 × 10 = 30 years

Check ⇒

Five years ago:

Son's age = x - 5 = 10 - 5 = 5

Father's age = 3x - 5 = 30 -5 = 25

5 × 5 = 25

25 = 25

L.H.S = R.H.S

Hence, verified.

The answer is correct.

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