the age of father is 3 years more than 3 times of his son,3 years hence the age of father will be 10 years more than twice the age of his son.Find their present ages ! plz answer fast tmrrw is my FA-1
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Let father's age be 'x' and his sons age be 'y'.
According to 1st condition,
x=3+3y.
x-3y=3. (1)
According to 2nd condition,
3+x=10+2y.
x-2y=7. (2)
Subtract (1) from (2)
x-2y=7
-x-3y=3
(-). (+). (-)
-------------
y=4
Put y=4 in eqn (2)
x-2(4)=7
x-8=7
x=15 years
I may be wrong because this answer doesn't make sense.But if my ans is right plz plz plz make this as brainliest answer
According to 1st condition,
x=3+3y.
x-3y=3. (1)
According to 2nd condition,
3+x=10+2y.
x-2y=7. (2)
Subtract (1) from (2)
x-2y=7
-x-3y=3
(-). (+). (-)
-------------
y=4
Put y=4 in eqn (2)
x-2(4)=7
x-8=7
x=15 years
I may be wrong because this answer doesn't make sense.But if my ans is right plz plz plz make this as brainliest answer
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