Math, asked by Anonymous, 1 year ago

The age of father is 3 years more than 3 times the son age. 3 years hence, age of father is 10years more than twice the age of son. find their present age.


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Answers

Answered by Jawwad20
2
ur ans

Present

Let the son's age be x.

Then, according to the condition given, father's age = 3x + 3

3 years later

Son's age= x + 3

Father's age = 3x + 3 + 3 = 3x + 6

According to the condition given,

3x + 6 = 10 + 2 ( x + 3 )

3x + 6 = 10 + 2x + 6

x = 10

Thus, the son's present age is 10 years and the father's age is 3(10) + 3 = 33 years.

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Answered by aaravvarshney
6
HERE IS YOUR ANSWER☺️ DEAR

Let the son's age be x.

Then, father's age = 3x + 3

AFTER 3 years,

Son's age= x + 3

Father's age = 3x + 3 + 3 = 3x + 6
given,
3x + 6 = 10 + 2 ( x + 3 )

3x + 6 = 10 + 2x + 6
【x = 10】

son's present age is 10 years and the father's age is 3(10) + 3 = 33 years.

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