the age of father is 3years more than 3 times the age of son 3 years hence fathers age will exceed twice the age of son by 13 years what will be their ages after 14 years
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Hi Shashi ,
Let f be father's present age
Let s be son's age
NOTE : " 3 years hence " means after 3 years
Given
f = 3+3s
f+3 = 2(s+3) + 13
solving
3+3s+3 = 2s +6+13
s = 13
f = 3+3s = 3+39 = 42
so their ages after 14 years are
father = f+14 = 42+14 = 56 years
son = s+14 = 13+14 = 27 years
Hope it helped.
Let me know if any doubts.
Cheers !!!
Let f be father's present age
Let s be son's age
NOTE : " 3 years hence " means after 3 years
Given
f = 3+3s
f+3 = 2(s+3) + 13
solving
3+3s+3 = 2s +6+13
s = 13
f = 3+3s = 3+39 = 42
so their ages after 14 years are
father = f+14 = 42+14 = 56 years
son = s+14 = 13+14 = 27 years
Hope it helped.
Let me know if any doubts.
Cheers !!!
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