Math, asked by ritikashivhare0305, 8 months ago

the age of father is 4 time the age of son.5 years hence the age of father will be three times the age of his son find the present ages​

Answers

Answered by SamanwitaC
0

Step-by-step explanation:

let x be father's present age and y be son's present age

x=4y. -( eq1)

x+5=3(y+5){substituting value of x }

4y+5=3y+15

4y-3y=15-5

y=10 years

x=4×10

=40 years

Answered by PixleyPanda
2

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20

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