Math, asked by prealpha72, 1 year ago

The age of father is 4 times that of his son.5 years ago his age of the father was 7 times that of his son. find there present age

Answers

Answered by piyushraj34

let age of son =x father age will be 4x seven yrs ago age of son =x-7 father age =4x-7 a/q (x-7)*7=4x-7 by solving we get x=14 son age :14 father age :56 yrs

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