Question

The age of father is 40 years more than that of his son.After 5 years,father's age will be thrice his son's age.Find their present ages.

Answer 1

[x+5][3x+45]=0

3x^2 +45x+15x+225=0

3x^2+60x+225=0

Answer 2

▁ ▂ ▄ ▅ ▆ ▇ █ SOLUTION █ ▇ ▆ ▅ ▄ ▂ ▁

▼Let

• The present age of father be X+40
• the present age of his son be X

After 5 years the father will be thrice of his son

• according to the question

$⇒(x + 40) + 5 = 3(x + 5) \\ \\ ⇒</h3><h3>x + 45 = 3x + 15 \\ \\ ⇒</h3><h3>3x - x = 45 - 15 \\ \\ ⇒</h3><h3>2x = 30 \\ \\ </h3><h3>⇒</h3><h3>x = 15$

HENCE:-

• The present age of father=40+15=55years
• The present age of his son=15 years