The age of father is double that of his son 10 years ago the age of
father is 3 times his son. Find the current ages of son and father.
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let the current age of son be x
and the current age of father is 2x
according to questions...10 years ago
the age of son = x-10
and the age of father = (2x-10 )3
= (2x-10) 3 = x- 10
= 6x - 30 = x -10
= 6x - x = -10 + 30
= 5x = 20
= x = 4
therefore the current age of son is 4 years
and father is 2x = 2x4 = 8 years......
........hope helps you......
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