Math, asked by veer352920, 1 year ago

The age of father is double the age of his son. 5years ago father was thrice as old as his son. Find their present age.​

Answers

Answered by Aarush0911
3

Step-by-step explanation:

Two years ago son's age= x-2.

His Father's age at that time = 3(x-2).

Present age of Father = 3x-6+2=3x-4

Two years hence father's age=3x-4+2=3x-2.

Two years hence son's age = x+2.

Given :-5*(x+2)=2*(3x-2)

5x + 10= 6x - 4

10+4=6x-5x

14=x

SON'S PRESENT AGE : 14 years.

FATHER'S S Present AGE: 38 years.

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