Math, asked by divyansha2625, 3 months ago

The age of father is double the age of son. If their total age is 75. How old father is ​


shahbhavya0097: Let the age of father be x years
Let the age of his son be y years
Hence,
x+y=75 —(1)
y=75-x —(2)
The difference between their ages:
y-x= (75-x)-x = 75–2x —(3)
According to the second statement,
When the son’s age = y,
(75-x) + (75–2x)+y = 125
150 - 3x + y = 125
3x-y = 25 —(4)
Adding (1) and (4), we get
4x = 100
Hence, x=25 years
y = 75–25 = 50 years
Present age of son = 25 years
Present age of father = 50 years

Answers

Answered by srinidhi3000
0

Answer:

Father's age=50 years

Son's age=25 years

Step-by-step explanation:

Given:-

Let the father's age be x and son's age be y.

x=2y

x+y=75

Since x=2y, substitute 2y in place of x.

Now:-

2y+y=75

3y=75

y=75/3

y=25

Son's age=25 years

Father's age will be 75-25=50 years

Hope it helps you!

Answered by yadavanant2312
0

Step-by-step explanation:

this is answer of qurstion

Attachments:
Similar questions