the age of father is equal to the sum of the ages of his 5 children.After 15 years the sum of the ages of the children will be twice the age of the father.Find the age of the father?
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let the sum of present ages of 5 children be x
age of father= x
after 15 years sum of age of 5 children= 15×5 +x
=75+x
age of father= x+15
a/q
75+x=2(x+15)
75+x=2x+30
75-30=2x-x
45= x
therefore present age of father= 45 years.ans
age of father= x
after 15 years sum of age of 5 children= 15×5 +x
=75+x
age of father= x+15
a/q
75+x=2(x+15)
75+x=2x+30
75-30=2x-x
45= x
therefore present age of father= 45 years.ans
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