Question

The age of father is twice that of elder daughter.Ten years hence the age of father will be three times that of the younger daughter.If the difference of ages of two daughters is 14 years then what is the present age of father

Answer 1

Age Difference of Two Daughters=14 years

Let Age of Elder Daughter=x

Let Age of Younger Daughter=y

X-Y=14

X=14+Y

Age of Elder Daughter=x=14+y years

Age of Younger Daughter=y years

Age of Father is 2 times age of Elder Daughter.

Age of Father=2×Age of Elder Daughter

=2(14+y) years

Ten Year Hence,

Age of Father=2(14+y)+10 years

Age of Younger Daughter=y+10 years

Father age will be 3×Youger daughter age after 10 years

2(14+y)+10=3(y+10)

28+2y+10=3y+30

38-30=3y-2y

8=y

Age of Father=2(14+y)

=2(14+8)

=2×22

=44

Age of Father=44 years