Question

The amount of naoh required to prepare 70litres if 0.5 n solution is

Answer 1

Answer:

Explanation:

60 litres of 0.5M solution needs 60 x 0.5 = 30 moles or 30 x 40 (molar mass of NaOH) = 1200 gram of pure NaOH .but we have wet NaOH having 10 % water or 90 % purity ..........hence requirement will be 100 x 1200 / 90 = 1333.33 grams or 1.333 kg approx. of wet NaOH .