the age of father is twice the age of the elder son.ten years hence the age of the younger son if the difference of ages of the two sons is 15 years then find the age of father
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Let the elder son be x
father = 2x
y = younger son=(x-15)
10 years later
2x+10=3(x-15+10)
2x+10=3(x-5)
3x-2x=25
x=25
y=10
father = 50
father = 2x
y = younger son=(x-15)
10 years later
2x+10=3(x-15+10)
2x+10=3(x-5)
3x-2x=25
x=25
y=10
father = 50
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