Question

The age of father is twice the sum of the ages of his two children's. After 20 years, his age will be equal to the sum of ages of his children's find age of father

Answer 1

Hey!

Let the age of Father be x
and the sum of the age of son be y

• The age of father is twice the sum of the ages of his two children's.



x = 2y .... ( i )

• After 20 years, his age will be equal to the sum of ages of his children's.

° After 20 years , their age will be

Father's age :- ( x + 20 )

Sum of two son's age :- ( y + 20 + 20 )
:- ( y + 40 )



( x + 20 ) = ( y + 40 )

x - y + 20 - 40 = 0

x - y - 20 = 0 ...... ( ii )


Putting value of x from ( i ) in ( ii )

x - y - 20 = 0


2y - y - 20 = 0

y = 20

Putting value of y in ( i )

x = 2y

x = 2 × 20

x = 40

So, the present age of father is 40 years !!

Answer 2

Answer:

Step-by-step explanation:

Given :-

The age of father is twice the sum of the ages of his two children's.

After 20 years, his age will be equal to the sum of ages of his children.

To Find :-

Father's present age

Solution :-

Let the present age of father and his two children be x, y and z years.

According to the Question,

⇒ x = 2 (y + z)            …(i)

After 20 years,

(x + 20) = (y + 20) + (z + 20)

⇒ y + z + 40 = x + 20

⇒ y + z = x – 20

Putting (y + z) value in Eq. (i)

⇒ x = 2 (y + z)

⇒ x = 2 (x -20)

⇒ x = 2x – 40

⇒ x = 40

Hence, the present age of father is 40 years.