The age of husband is obtained by interchanging the digits in the age of his wife.if the different between their ages is one eleventh of the sum of their ages, then the age of the wife is
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Suppose her age is expressed as 10A+B where A and B are integers.
Then her husband's age is 10B + A
The sum is 10A + B + 10B + A = 11(A+B)
The difference is 10B+A -(10A+B) = 9B - 9 A
The difference is 1/11 the sum so
9B - 9A = (1/11)(11(A+B))
9B - 9A = A + B
8B = 10A
4B = 5A
Remember A and B have to be integers.
What are two integers that work for this? (Answer below)
4B = 5A
4(5) = 5(4)
That is, her age is 45 and his is 54. Does it work
Then her husband's age is 10B + A
The sum is 10A + B + 10B + A = 11(A+B)
The difference is 10B+A -(10A+B) = 9B - 9 A
The difference is 1/11 the sum so
9B - 9A = (1/11)(11(A+B))
9B - 9A = A + B
8B = 10A
4B = 5A
Remember A and B have to be integers.
What are two integers that work for this? (Answer below)
4B = 5A
4(5) = 5(4)
That is, her age is 45 and his is 54. Does it work
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