Math, asked by Basantasahoo, 11 months ago

The age of leena and heena age in ratio 7:5 Ten years hence the ratio of their age will be 9:7find their present age .​

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Answered by brunoconti
2

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Answered by AmritanshuKeshri31
2
Question:- The age of leena and heena age in ratio 7:5 Ten years hence the ratio of their age will be 9:7find their present age .

Solution:- The ratio of the present ages of Leena and Heena = 7:5

Let the age of Leena be 7x years and Heena be 5x years.

Ten years later their ages will be 7x +10 years and 5x + 10 years.

but the ratio of their ages after ten years is given as 9:7.

let their ages be 9x and 7x

∴9x + 7x = 7x + 10 + 5x + 10  

⇒9x = -7x + 7x + 10 + 5x + 10

⇒9x -5x = 10 + 10

⇒4x = 20

⇒x = 20/4 = 5

∴x = 5

Answer:-

∴The age of Leena = 7x = 7× 5 = 35 years

and, Heena`s age = 5x = 5× 5 = 25 years.
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