Question

The age of leena and heena are in ratio 7:5 ten years hence the ratio of thier ages will be 9:7 find thier present ages

Answer 1

let the present age of Leena and Heena be 7x and 5x
after 10 yrs
( 7x+10)/(5x+10) = 9/7
49x+70=45x+90
4x = 20
x = 5
their present ages will be
Leena = 7x = 35
Heena = 5x = 25

Answer 2

Answer:

The Present ages are -

• Leena = 35 years
• Heena = 25 years

Explanation:

Given :

Ages of Leena and Heena are in Ratio = 7 : 5

Ratio after 10 Years = 9 : 7

To Find :

Their present Ages

Solution :

Let the present Ages be -

• Leena as 7x
• Heena as 5x

$\rule{300}{1.5}$

➡ (7x + 10)/(5x + 10) = 9/7

➡ 7(7x + 10) = 9(5x + 10)

➡ 49x + 70 = 45x + 90

➡ 49x - 45x = 90 - 70

➡ 4x = 20

➡ x = 20/4

➡ x = 5

$\rule{300}{1.5}$

Heena's age =

➡ 5 × 5

➡ 25

$\rule{300}{1.5}$

Leena's age =

➡ 7 × 5

➡ 35

$\therefore$ The Present ages are -

• Leena = 35 years
• Heena = 25 years