Question

The age of leena and heena are in ratio 7:5 ten years hence the ratio of theri age 9:7 find the present age

Answer 1

Hi there!
Here's the answer:

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Let present age of Leena = 7x
and present age of Helena = 5x

(°•° Ratio of their ages =7:5)

10 years hence, i.e., after 10 years
Age of Leena = 7x+10
Age of Heena = 5x+10

Given, (7x+10)/(5x+10) = (9/7)

=> 7(7x+10) = 9(5x+10)
=> 49x+70 = 45x+90
=> 4x = 20
=> x= 5

•°• Present age of Leena 7x = (7×5) = 35
and present age of Helena = 5x = (5×5) = 25

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Hope it helps

Answer 2

Answer:

The Present ages are -

Leena = 35 years

Heena = 25 years

Step-by-step explanation:

Given :

Ages of Leena and Heena are in Ratio = 7 : 5

Ratio after 10 Years = 9 : 7

To Find :

Their present Ages

Solution :

Let the present Ages be -

• Leena as 7x
• Heena as 5x

$\rule{300}{1.5}$

➡ (7x + 10)/(5x + 10) = 9/7

➡ 7(7x + 10) = 9(5x + 10)

➡ 49x + 70 = 45x + 90

➡ 49x - 45x = 90 - 70

➡ 4x = 20

➡ x = 20/4

➡ x = 5

$\rule{300}{1.5}$

Heena's age =

➡ 5 × 5

➡ 25

$\rule{300}{1.5}$

Leena's age =

➡ 7 × 5

➡ 35

$\therefore$ The Present ages are -

• Leena = 35 years
• Heena = 25 years