The age of M after 8 years is 50% more than the age of N at that time and age of Q is 2 years younger than N. If M's present age is 2 years more than the twice of Q's present age, then what is the sum of present age of M,N and Q?
Answers
Given : The age of M after 8 years is 50% more than the age of N at that time and age of Q is 2 years younger than N. M's present age is 2 years more than the twice of Q's present age,
To Find : what is the sum of present age of M,N and Q?
Solution:
Present age of M = M
present age of N = N
Present age of Q = N - 2
M's present age is 2 years more than the twice of Q's present age,
M = 2 + 2(N - 2)
=> M = 2 + 2N - 4
=> M = 2N - 2
The age of M after 8 years is 50% more than the age of N at that time
M + 8 = ( N + 8) ( 1 + 50/100)
=> M + 8 = (N + 8) (3/2)
=> 2M + 16 = 3N + 24
=> 2M = 3N + 8
M = 2N - 2
=> 2M = 4N - 4
4N - 4 = 3N + 8
=> N = 12
M = 2(12) - 2 = 22
M = 22
N = 12
Q = 10
M + N + Q = 22 + 12 + 10 = 44
sum of present age of M,N and Q = 44 years
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