Math, asked by Rajeshraja33871, 1 year ago

The age of Mohan is twice square of his son sohans age. After 8 years the age of Mohan will be 4 years more than three times of his son sohans age. Find their present age.

Answers

Answered by dugarsuzal79pdg6h4
2
Let the present son sohans age be x years
Present Age of mohan 2(x) ^2............. (I)
After 8 years
Age of son sohans be x+8
Age of mohan be 4+3(x+8)
Present age of mohan 4+3(x+8)-8........ (ii)
I is equal to ii
2xsquare=4+3(x+8)-8
Solve and u will get the answer
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