Question

the age of Monu is one third the age of his mother if the sum of their ages is 48 years find the age of both

Answer 1

let present age of monu be x years nd his mother's age be 3x years.

so,.

x +3x= 48
4x=48
x=12

hence monu's present age is 12 years and his mother's present age is 36 years.

MARK ME AS BRAINLIEST

Answer 2

Let Mother Age=X years
Then Monu Age=1/3×x=X/3 years
Sum of their Age=48
Means
$x + \frac{x}{3} = 48 \\ = \frac{3x + x}{3} = 48 \: \: \: \: \: (lcm = 3) \\ = \frac{4x}{3} = 48 \\ = 4x = 48 \times 3 \\ x = 48 \times \frac{3}{4} \\ x = 36$
we get X=36
Mother Age=36
Monu Age=1/3×36=12 years

Mother=36 years
Monu=12 years