Question

the age of monu is the 1/3 age of his mother if the sum of their ages is 48 years find the age of each

Answer 1

$\large \underline{ \underline{ \sf \: Answer : \: \: \: }}$

$\star$Monu's age = 12

$\star$Monu's mother age = 36

$\large \underline{ \underline{ \sf \: Explaination : \: \: \: }}$

Let ,

The age of monu mother = x

So , the age of monu = x/3

According to the question ,

$\to \sf x + \frac{x}{3} = 48 \\ \\ \to \sf</p><p></p><p>4x = 48×3 \\ \\ \to \sf</p><p></p><p>4x = 144 \\ \\ \to \sf</p><p></p><p>x = \frac{144}{4} \\ \\ \to \sf x = 26$

$\therefore$The age of monu mother is 36 years and age of monu is 36/3 i.e 12 years

Answer 2

Answer:

Let the age of Monu's mother be 'x'

This implies age of Monu is 1/3 of x which is ( x/3 )

Given that, Sum of their ages is 48 years. Using this condition we get,

⇒ x + x/3 = 48

Taking LCM we get,

⇒ ( 3x + x )/3 = 48

⇒ 4x/3 = 48

⇒ 4x = 48 × 3

⇒ 4x = 144

⇒ x = 144/4

⇒ x = 36

Therefore the age of Monu's mother is 36 years.

Age of Monu = x/3

⇒ Age of Monu = ( 36/3 )

⇒ Age of Monu = 12 years

Therefore age of Monu is 12 years