Question

the age of mother and daughter are 31 and 7 years respectively. The numbers of years in which the mother's age will be 3/2 times of the daughter age
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Answer 1

Answer:

The ages of a mother and daughter are 31 and 7 years respectively.

In how many years will the mother's age be 3/2 times that of daughter

:

Let y = no. of years for this to be true

:

y + mothers age = 3%2F2* y + daughter's age

the equation

y + 31 = 3%2F2(y + 7)

Get rid of the denominator, multiply both sides by 2

2(y+31) = 3(y+7)

:

2y + 62 = 3y + 21

:

62 - 21 = 3y - 2y

:

y = 41 yrs for this to be true

:

:

See if it works out

41 + 31 = 3%2F2(41+7

72 = 3%2F2(48)

72 = 3(24); confirms our solution

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