Question

The area of a rectangular playground is 88 m. Its length is 11 m. What is the perimeter of the
playground?​

Answer 1

Given :

• The area of a rectangular playground is 88 m.
• Length of the rectangular playground is 11 m.

To find :

• The perimeter of the playground =?

Formula Used :

• Area of Rectangle = length x breadth
• Perimeter of the rectangle = 2 (length + breadth)

Step-by-step explanation :

We know that,

Area of Rectangle = length x breadth

It is Given that,

The area of a rectangular playground is 88 m.

Length of the rectangular playground is 11 m.

Substituting the values in the above formula, we get,

88 = 11 × breadth

breadth = 88/11

breadth = 8.

Therefore, We got the breadth of rectangular playground = 8 m.

Now,

Perimeter of the rectangle = 2 (length + breadth)

Substituting the values in the above formula, we get,

= 2(11 + 8)

= 2(19)

= 38.

Therefore, Perimeter of the rectangular playground = 38 m.

Answer 2

$\huge\underline\mathtt\color{gold} Given$

• The area of the rectangular playground is 88m.
• The length of the rectangular playground is 11m.

$\huge\underline\mathtt\color{gold}To Find$

• The perimeter of the playground.

$\huge\underline\mathtt\color{gold}FormulaUsed$

• Area of the rectangle=Length×Breadth.

• Perimeter of the rectangle=2×(Length+Breadth)

$\huge\underline\mathtt\color{gold} Solution$

Let the breadth be x.

By condition,

Area of the rectangle=88

$\sf{\implies(length \times breadth) = 88}$

$\sf{\implies 11 \times x = 88}$

$\sf{\implies x = \cancel\frac{88}{11} }$

$\sf{\implies x = 8}$

Now,the perimeter of the rectangle is

$\sf{ = 2 \times (length + \: breadth)}$

$\sf{ = 2 \times (11 + 8)}$

$\sf{ = 2 \times 19}$

$\sf{ = 38}$

Therefore, the perimeter of the rectangular playground is 38m.