Question

The age of mother and daughter are in same ratio 9:4 five years ago age of th mother was 10 years more than twice the age of her daughter. Find their present age.

Answer 1

Let present age of mother and daughter be 9X and 4X years respectively.


Five years ago age of mother = ( 9X - 5 ) years.



Five years ago age of daughter = ( 4X - 5 ) years.




According to the question,



2 ( 4X - 5 ) + 10 = 9X - 5



8X - 10 + 10 = 9X - 5



9X - 8X = 5


X = 5 years.



Present age of mother= 9X = 45 years.


And,


Present age of daughter = 4X = 20 years.

Answer 2

yoυr anѕwer !!

ʀᴀᴛɪᴏ ᴏғ ᴀɢᴇs ᴏғ ᴍᴏᴛʜᴇʀ ᴀɴᴅ ᴅᴀᴜɢʜᴛᴇʀ = 9:4

ʟᴇᴛ ᴛʜᴇ ᴄᴏᴍᴍᴏɴ ʀᴀᴛɪᴏ = x

ᴍᴏᴛʜᴇʀ's ᴀɢᴇ = 9x

ᴅᴀᴜɢʜᴛᴇʀ's ᴀɢᴇ = 4x

10 ʏᴇᴀʀs ᴀɢᴏ:

ᴍᴏᴛʜᴇʀ's ᴀɢᴇ = 9x - 5

ᴅᴀᴜɢʜᴛᴇʀ's ᴀɢᴇ = 4x - 5

ᴀᴛǫ ʏᴏᴜʀ ᴇǫᴜᴀᴛɪᴏɴ ʙᴇᴄᴏᴍᴇs:

$= > 9x - 5 = 2(4x - 5) + 10 \\ \\ = > 9x - 5 = 8x - 10 + 10 \\ \\ = > 9x - 5 = 8x \\ \\ = > 9x - 8x = 5 \\ \\ = > 1x = 5 \\ \\ = > x = 5$

ᴘʀᴇsᴇɴᴛ ᴀɢᴇs:

ᴅᴀᴜɢʜᴛᴇʀ's = 4x = 4 × 5 = 20 ʏᴇᴀʀs

ʜᴇʀ ᴍᴏᴛʜᴇʀ's = 9x = 9 × 5 = 45 ʏᴇᴀʀs

тнanĸѕ !!