Question

The age of Seema and her mother together is 72. If the mother’s age is three times that of Seema ,what are​

Answer 1

Answer:

let seemas age be y

let her mother's age be x

according to the condition given,

$x + y = 72$

.... equation 1 .

according to the second condition given,

$x = 3y \\ x - 3y = 0$

...... equation two

on subtracting both the equations

$x + y = 72 \\ - (x - 3y = 0) \\ 4y = 72 \\ y = \frac{72}{4} \\ y = 18$

therefore Seema's age is 18.

substituting y is equal to 18 in equation 1

$x + y = 72 \\ x + 18 = 72 \\ x = 72 - 18 \\ x = 54$

therefore Seema's mother's age is 54.

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Answer 2

Step-by-step explanation:

seema's age =x

So, her mother's age =3x

sum of the her age's =72

=x+3x=72

=4x=72

x=72/4=18

seema's age x =18

So,seema's mother age =18*3=54

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