Math, asked by alishathakur46, 8 months ago

The age of Sudha and Mona are in the ratio 3:4. Five years ago their ages were 2:3. Find their present ages​

Answers

Answered by Anonymous
111

Given

  • The age of Sudha and Mona are in ratio 3:4
  • After five years their ages were 2:3

Find out

  • Find the present ages of Sudha and Mona

Solution

Let the present age of Sudha be 3x and Mona be 4x

**According to the given condition**

  • After five years ago
  • Sudha's age = (3x - 5)
  • Mona's age = (4x - 5)

→ 3x - 5/4x - 5 = 2/3

→ 3(3x - 5) = 2(4x - 5)

→ 9x - 15 = 8x - 10

→ 9x - 8x = 15 - 10

→ x = 5

Hence,

  • Present age of Sudha = 3x = 15 years
  • Present age of Mona = 4x = 20 years
Answered by SarcasticL0ve
62

Given:-

  • The age of Sudha and Mona are in the ratio 3:4.

  • Five years ago their ages were 2:3.

To find:-

  • Present age of sudha and Mona.

Solution:-

Let Present age of sudha be 3x.

And, Present age of Mona be 4x.

According to Question:-

Their ages after 5 years ago :-

Sudha's age after 5 years = (3x - 5)

Mona's age after 5 years = (4x - 5)

Five years ago their ages were 2:3 :-

:\implies\sf \dfrac{3x - 5}{4x - 5} = \dfrac{2}{3}

Cross Multiplication:-

:\implies\sf 3(3x - 5) = 2(4x - 5)

:\implies\sf 9x - 15 = 8x - 10

:\implies\sf 9x - 8x =15 - 10

:\implies\sf \bf{x = 5}

Therefore,

  • Present Age of sudha = (3x) = 3 × 5 = 15 years

  • Present Age of Mona = (4x) = 4 × 5 = 20 years

Hence, Solved!!

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Anonymous: Perfect!
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