The age of Sudha and Mona are in the ratio 3:4. Five years ago their ages were 2:3. Find their present ages
Answers
Answered by
111
Given
- The age of Sudha and Mona are in ratio 3:4
- After five years their ages were 2:3
Find out
- Find the present ages of Sudha and Mona
Solution
★ Let the present age of Sudha be 3x and Mona be 4x
**According to the given condition**
- After five years ago
- Sudha's age = (3x - 5)
- Mona's age = (4x - 5)
→ 3x - 5/4x - 5 = 2/3
→ 3(3x - 5) = 2(4x - 5)
→ 9x - 15 = 8x - 10
→ 9x - 8x = 15 - 10
→ x = 5
Hence,
- Present age of Sudha = 3x = 15 years
- Present age of Mona = 4x = 20 years
Answered by
62
Given:-
- The age of Sudha and Mona are in the ratio 3:4.
- Five years ago their ages were 2:3.
To find:-
- Present age of sudha and Mona.
Solution:-
Let Present age of sudha be 3x.
And, Present age of Mona be 4x.
According to Question:-
★ Their ages after 5 years ago :-
Sudha's age after 5 years = (3x - 5)
Mona's age after 5 years = (4x - 5)
★ Five years ago their ages were 2:3 :-
Cross Multiplication:-
Therefore,
- Present Age of sudha = (3x) = 3 × 5 = 15 years
- Present Age of Mona = (4x) = 4 × 5 = 20 years
★ Hence, Solved!!
Anonymous:
Perfect!
Similar questions