Question

The age of Sudha and Mona are in the ratio 3:4. Five years ago their ages were 2:3. Find their present ages​

Answer 1

Given

• The age of Sudha and Mona are in ratio 3:4
• After five years their ages were 2:3

Find out

• Find the present ages of Sudha and Mona

Solution

★ Let the present age of Sudha be 3x and Mona be 4x

**According to the given condition**

• After five years ago
• Sudha's age = (3x - 5)
• Mona's age = (4x - 5)

→ 3x - 5/4x - 5 = 2/3

→ 3(3x - 5) = 2(4x - 5)

→ 9x - 15 = 8x - 10

→ 9x - 8x = 15 - 10

→ x = 5

Hence,

• Present age of Sudha = 3x = 15 years
• Present age of Mona = 4x = 20 years

Answer 2

Given:-

• The age of Sudha and Mona are in the ratio 3:4.

• Five years ago their ages were 2:3.

To find:-

• Present age of sudha and Mona.

Solution:-

Let Present age of sudha be 3x.

And, Present age of Mona be 4x.

According to Question:-

★ Their ages after 5 years ago :-

Sudha's age after 5 years = (3x - 5)

Mona's age after 5 years = (4x - 5)

★ Five years ago their ages were 2:3 :-

$:\implies\sf \dfrac{3x - 5}{4x - 5} = \dfrac{2}{3}$

Cross Multiplication:-

$:\implies\sf 3(3x - 5) = 2(4x - 5)$

$:\implies\sf 9x - 15 = 8x - 10$

$:\implies\sf 9x - 8x =15 - 10$

$:\implies\sf \bf{x = 5}$

Therefore,

• Present Age of sudha = (3x) = 3 × 5 = 15 years

• Present Age of Mona = (4x) = 4 × 5 = 20 years

★ Hence, Solved!!

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