Math, asked by xXBhumikaxX, 3 months ago

The age of the father is 3 years more than three times the age of the son.Three years hence,fathers age will exceed twice the age of the son by 13 years.What will be their ages after 4 years.


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Answers

Answered by kumkumjaswara1
2

Step-by-step explanation:

The present age of father is three years more than three times the age of the son. Also again from the question it's given as, After 3 years, father's age will be (x + 3) years and son's age will be (y + 3) years. Hence, The present age of father = 33 years and the present age of his son = 10 years.

Answered by Anonymous
50

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Let the son's age be x

Then , according to the condition,

father's age = 3x+3

3 years later:

Son's age = x+3

Father's age =3x+3+3=3x+6

According to the condition given , 

3x+6 = 10+2(x+3)

3x+6 = 10+2x+6

x = 10

Thus , the son's present age is 10 years and the father's age is 

=> 3x+3

=> 3×10+3

=> 33 years.

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