The age of the father is three times the age of his son 15 years later the father will be 2 times his son, then know the sum of his age.
Answers
A father is three times as old as his son. In 12 years time, he will be twice as old as his son. What is the present age of the father and son?
In this problem, we can assign X to the son’s age and Y to the father’s.
We know that a father is 3 times as old as his son.
Therefore, we can create the equation 3X=Y.
We must now create a second equation from the remaining information, being “In 12 years he will be twice as old as his son”. We know we can add 12 years, along with including 2X in the equation.
The equation that we can gather from this second piece of information will be Y=2X+12. This is because the father’s age, in 12 year’s time, will be twice that of the child.
Now we have our two equations:
Y=3X
Y=2X+12
Because both equations are set equal to the age of the father, we can use the substitution method to solve in terms of the son’s age, as follows:
3X = 2X+12
Now we subtract 2X from each side to isolate the variable:
X=12
The son’s age is therefore 12 years old. Should we plug that age back into our first equation, we get Y=3(12) or Y=36.
The father’s present age is 36, while the son’s present age is 12.
Answer:
sum of their age is 15 + 45 = 60
Step-by-step explanation:
let his sons age be X
so his father's age will be 3X
equation formed = 3X + 15 = 2(X + 15)
= 3X + 15 = 2X + 30
= 3X - 2X = 30 - 15
= X = 15
his sons age is 15yrs
his father's age is =15*3
= 45
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