Math, asked by rsbadgujar19, 4 months ago

The age of the son is 30 years less than the age of the mother if after 10 years the ratio of age of mother and son becomes 3: 1 then the present age of the mother becomes ..... years.​

Answers

Answered by cornea
0

Step-by-step explanation:

let the age of son be x

then the age of mother will be x+30

age of son after 10 years = x+ 10

age of mother after 10 years= x+30+10

A/q

x+30+10=3(x+ 10)

x+ 40= 3x+30

40-30=3x-x

10=2x

10/2=x

5=x

so present age of mother is x+30=5+30

=35

age of mother after ten years = 45

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